en:cs:modelling_multi-phased_electrical_system_interconnexion

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en:cs:modelling_multi-phased_electrical_system_interconnexion [2021/04/12 09:18] – [Typescript code sketches] fraggleen:cs:modelling_multi-phased_electrical_system_interconnexion [2024/04/18 20:39] (Version actuelle) – [Quick and dirty mathematics background and rationale] fraggle
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 Let's call $ A = (p_{a}, V_{a}, I_{a}, Iph_{a}) $ and $ B = (p_{b}, V_{b}, I_{b}, Iph_{b}) $ two multi-phased electrical systems where $ p_{a},p_{b} \in \mathbb{N} $ are respectively the number of phases, $ V_{a}, V_{b} \in \mathbb{N} $ are the voltage per phase, $ I_{a}, I_{b} \in \mathbb{N} $ are the total intensity and $ Iph_{a}, Iph_{b} \in \mathbb{N} $ the intensity per phase.\\  Let's call $ A = (p_{a}, V_{a}, I_{a}, Iph_{a}) $ and $ B = (p_{b}, V_{b}, I_{b}, Iph_{b}) $ two multi-phased electrical systems where $ p_{a},p_{b} \in \mathbb{N} $ are respectively the number of phases, $ V_{a}, V_{b} \in \mathbb{N} $ are the voltage per phase, $ I_{a}, I_{b} \in \mathbb{N} $ are the total intensity and $ Iph_{a}, Iph_{b} \in \mathbb{N} $ the intensity per phase.\\ 
-We always have: $ I_{a} = p_{a} \times Iph_{a} $ and $ I_{b} = p_{b} \times Iph_{b} $. So the intensities properties can be deduced one from the other+The intensities properties can be deduced one from the other: $ I_{a} = p_{a} \times Iph_{a} $ and $ I_{b} = p_{b} \times Iph_{b} $.
  
   * $ A $ and $ B $ are interconnected serially : $ A \triangleleft \triangleright B $.    * $ A $ and $ B $ are interconnected serially : $ A \triangleleft \triangleright B $. 
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   * $ I_{a} > I_{b} \land p_{a} < p_{b} \land p_{a}, p_{b} \in \{2,3\} \land I_{b} \ mod \ p_{a} \neq 0 \Rightarrow Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ ;   * $ I_{a} > I_{b} \land p_{a} < p_{b} \land p_{a}, p_{b} \in \{2,3\} \land I_{b} \ mod \ p_{a} \neq 0 \Rightarrow Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ ;
   * $ I_{a} < I_{b} \land p_{a} > p_{b} \land p_{a}, p_{b} \in \{2,3\} \land I_{a} \ mod \ p_{b} \ne 0 \Rightarrow Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ ;   * $ I_{a} < I_{b} \land p_{a} > p_{b} \land p_{a}, p_{b} \in \{2,3\} \land I_{a} \ mod \ p_{b} \ne 0 \Rightarrow Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ ;
-We can expose at leat two cases where $ Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ if $ p_{a}, p_{b} \in \{2,3\} $+We can expose at least two cases where $ Iph_{A \triangleleft \triangleright B} \notin \mathbb{N} $ if $ p_{a}, p_{b} \in \{2,3\} $
  
 Let's say you only have $ Iph_{a}, Iph_{b} $ in $ A $ and $ B $. We can deduce $ I_{a}, I_{b} $ from them.\\  Let's say you only have $ Iph_{a}, Iph_{b} $ in $ A $ and $ B $. We can deduce $ I_{a}, I_{b} $ from them.\\ 
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  * Targeted to AC related values calculation.  * Targeted to AC related values calculation.
  */  */
-export default class ACElectricUtils {+export class ACElectricUtils {
   static amperageTotal(nbOfPhases: number, Iph: number): number {   static amperageTotal(nbOfPhases: number, Iph: number): number {
     return nbOfPhases * Iph;     return nbOfPhases * Iph;
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     Iph: Math.min(Car.Iph, ChargingStation.Iph),     Iph: Math.min(Car.Iph, ChargingStation.Iph),
     V: Math.min(Car.V, ChargingStation.V),     V: Math.min(Car.V, ChargingStation.V),
-    I: ElectricityUtils.calculateAmpTotal(this.nPhases, this.Iph), +    I: ACElectricUtils.amperageTotal(this.nPhases, this.Iph), 
-    P: ElectricityUtils.calculatePowerTotal(this.nPhases, this.Iph, this.V),+    P: ACElectricUtils.powerTotal(this.nPhases, this.Iph, this.V),
   };   };
 } }
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